x^2=9999

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Solution for x^2=9999 equation:



x^2=9999
We move all terms to the left:
x^2-(9999)=0
a = 1; b = 0; c = -9999;
Δ = b2-4ac
Δ = 02-4·1·(-9999)
Δ = 39996
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{39996}=\sqrt{36*1111}=\sqrt{36}*\sqrt{1111}=6\sqrt{1111}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{1111}}{2*1}=\frac{0-6\sqrt{1111}}{2} =-\frac{6\sqrt{1111}}{2} =-3\sqrt{1111} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{1111}}{2*1}=\frac{0+6\sqrt{1111}}{2} =\frac{6\sqrt{1111}}{2} =3\sqrt{1111} $

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